JEE Main 2014 Physics question

PhysicsGravitationJEE Main 2014

Four particles, each of mass M and equidistant from each other, move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is -

Answer: (C)

Solution

The particles sit at the corners of a square of side . Net force towards the centre on one particle \sqrt{2}$ + =

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-008746