JEE Main 2014 Physics question

A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?

(A)A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cmCorrect
(B)A screw gauge having 100 divisions in the circular scale and pitch as 1 mm
(C)A screw gauge having 50 divisions in the circular scale and pitch as 1 mm
(D)A meter scale

Answer: (A)

Solution

3.50 cm implies a least count of 0.01 cm. Vernier: LC $= S - V =

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Question ID VK-008748