At 25°C, the enthalpy of the following processes are given H_2(g)+O_2(g) 2OH(g) H^0 = 78 kJ mol^ -1 ; H_2(g)+...

Question

At 25°C, the enthalpy of the following processes are given H_2(g)+O_2(g) 2OH(g) H^0 = 78 kJ mol^ -1 ; H_2(g)+ 1 2 O_2(g) H_2O(g) H^0 = –242 kJ mol^ -1 ; H_2(g) 2H(g) H^0 = 436 kJ mol^ -1 ; 1 2 O_2(g) O(g) H^0 = 249 kJ mol^ -1 What would be the value of X for the following reaction ? ________ (Nearest integer) H_2O(g) H(g)+OH(g) H^0 = X kJ mol^ -1

Accepted Answer

499

JEE Main 2023 Chemistry question

Solution