At what pH, given half cell MnO_4^-(0.1 M) | M^ 2+ (0.001 M) will have electrode potential of 1.282 V ?...

Question

At what pH, given half cell MnO_4^-(0.1 M) | M^ 2+ (0.001 M) will have electrode potential of 1.282 V ? ________ (Nearest Integer) Given E^0_ MnO_4^-|Mn^ 2+ = 1.54 V, 2.303RT F = 0.059 V

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3

JEE Main 2023 Chemistry question

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