JEE Advanced 2010 Physics question
An -particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de Broglie wavelengths are and respectively. The ratio , to the nearest integer, is
Answer: 3
Solution
A particle of charge q and mass m accelerated from rest through a potential difference V gains kinetic energy , so its momentum is and its de Broglie wavelength is $λ =
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