Total number of geometrical isomers for the complex [RhCl(CO)(PPh_3)(NH_3)] is

JEE Advanced 2010 Chemistry question

Total number of geometrical isomers for the complex is

Answer: 3

Solution

Rh(I) is , and with these ligands it forms a four-coordinate square planar complex of the type (four different monodentate ligands a = Cl, b = CO, c = , d = ). In a square planar complex, fix ligand a; the

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Question ID VK-025825