If the distance of the point P(1, -2, 1) from the plane x + 2y - 2z = , where > 0, is 5, then the foot of the perpendicular from P to the plane is

JEE Advanced 2010 Mathematics question

If the distance of the point from the plane , where , is 5, then the foot of the perpendicular from P to the plane is

Answer: (A)

Distance ; since , . The foot of the perpendicular is for the value of t that puts it on the plane: $(1 + t) + 2(-2 + 2t) - 2(1 - 2t) = 10 ⇒ -5 +

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Question ID VK-025840