JEE Advanced 2011 Physics question

The wavelength of the first spectral line in the Balmer series of hydrogen atom is 6561 Å. The wavelength of the second spectral line in the Balmer series of singly-ionized helium atom is

(A)1215 ÅCorrect
(B)1640 Å
(C)2430 Å
(D)4687 Å

Answer: (A)

Solution

. First Balmer line of H (, ): . Second Balmer line of (, ): $ = 4R(14 -

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Question ID VK-025901