The freezing point (in °C) of a solution containing 0.1 g of K_3[Fe(CN)_6] (Mol. Wt. 329) in 100 g of water (K_f = 1.86 K kg mol^ -1 ) is

JEE Advanced 2011 Chemistry question

The freezing point (in °C) of a solution containing 0.1 g of (Mol. Wt. 329) in 100 g of water ( K kg ) is

Answer: (A)

\mathrm{K_3[Fe(CN)_6] \rightarrow 3K^+ + [Fe(CN)_6]^{3-}}, so the van't Hoff factor (complete dissociation). Molality mol kg⁻¹. T_fiK_fm$ =

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Question ID VK-025948