JEE Advanced 2012 Physics question
Two large vertical and parallel metal plates having a separation of 1 cm are connected to a DC voltage source of potential difference X. A proton is released at rest midway between the two plates. It is found to move at 45° to the vertical JUST after release. Then X is nearly
Answer: (C)
Solution
The proton experiences its weight mg vertically downward and the electric force eE horizontally (the plates are vertical). Moving at 45° to the vertical means the two forces are equal: $eE = mg
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