Let f(x) = cases x^2 | x |, & x 0 0, & x = 0 cases , x R , then f is

JEE Advanced 2012 Mathematics question

Let , , then f is

Answer: (B)

At x = 0: (bounded × 0), so f is differentiable at 0. At x = 2: , and changes sign at x = 2 with

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Question ID VK-026045