JEE Advanced 2012 Mathematics question

MathematicsThree Dimensional GeometryJEE Advanced 2012

The equation of a plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x − y + z = 3 and at a distance from the point (3, 1, −1) is

Answer: (A)

Solution

Any plane through the line of intersection is , i.e. . Distance from (3, 1, −1): $Missing argument for \dfrac\dfrac{|3(1 + λ) + (2 - λ) - (3 + λ) - (2 + 3λ)|}{Missing argument for \sqrt\sqrt{(1 + λ + (2 - λ + (3

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Question ID VK-026104