JEE Advanced 2013 Physics question
The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The 24th division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is
Answer: (B)
Solution
The zero lies between 5.10 and 5.15 cm, so one main scale division is 0.05 cm. 50 Vernier divisions = 2.45 cm, so 1 VSD = 0.049 cm. Least count
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