JEE Advanced 2013 Physics question
A particle of mass m is projected from the ground with an initial speed at an angle α with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial speed . The angle that the composite system makes with the horizontal immediately after the collision is
Answer: (A)
Solution
At the highest point the first particle moves horizontally with speed , at height . The second particle, thrown up with , has at that height speed \sqrt{u_0^2 - 2gH}\sqrt{u_0^2 - u_0^2\sin^2α}$ =
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