A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, y(x, t) = (0.01 m ) [(62.8 m^ -1 )x] [(628 s^ -1 )t]. Assuming π = 3.14, the correct statement(s) is (are)

JEE Advanced 2013 Physics question

A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, . Assuming π = 3.14, the correct statement(s) is (are)

(A)The number of nodes is 5.
(B)The length of the string is 0.25 m.Correct
(C)The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m.Correct
(D)The fundamental frequency is 100 Hz.

Answer: (B),(C)

Solution

m; Hz. In the fifth harmonic m (B true). The fifth harmonic has 5 loops and therefore 6 nodes, including the

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Question ID VK-026134