JEE Advanced 2013 Physics question

PhysicsNucleiJEE Advanced 2013

A freshly prepared sample of a radioisotope of half-life 1386 s has activity disintegrations per second. Given that ln 2 = 0.693, the fraction of the initial number of nuclei (expressed in nearest integer percentage) that will decay in the first 80 s after preparation of the sample is

Answer: 4

Solution

Decay constant . Fraction decayed in t = 80 s: $1 -

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Question ID VK-026140