JEE Advanced 2013 Mathematics question
Let . Then can take value(s)
Answer: (A),(D)
Solution
for k = 1, 2, 3, 4 is 1, 3, 6, 10, so the signs follow the pattern −, −, +, + repeating with period 4. Group the terms in fours: 1)^22)^23)^24)^2$ = 2(8m + 4) + 2(8m + 6)
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