JEE Advanced 2013 Physics question

Using the expression 2d sin θ = λ, one calculates the values of d by measuring the corresponding angles θ in the range 0 to 90°. The wavelength λ is exactly known and the error in θ is constant for all values of θ. As θ increases from 0°,

(A)the absolute error in d remains constant.
(B)the absolute error in d increases.
(C)the fractional error in d remains constant.
(D)the fractional error in d decreases.Correct

Answer: (D)

Solution

. Differentiating: and . As θ increases from 0 to 90°, decreases, so the fractional

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Question ID VK-026184