JEE Advanced 2013 Chemistry question

ChemistryEquilibriumJEE Advanced 2013

The of is at 298 K. The solubility (in mol/L) of in a 0.1 M solution is

Answer: (B)

Solution

\mathrm{Ag_2CrO_4 \rightleftharpoons 2Ag^+ + CrO_4^{2-}}, . In 0.1 M , Missing close brace[\mathrm{Ag^+$}]

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Question ID VK-026208