Match List I with List II and select the correct answer using the code given below the lists : List I P. ( 1...

Question

Match List I with List II and select the correct answer using the code given below the lists : List I P. ( 1 y^2 ( ( ^ -1 y) + y ( ^ -1 y) ( ^ -1 y) + ( ^ -1 y) )^2 + y^4 )^ 1/2 takes value Q. If cos x + cos y + cos z = 0 = sin x + sin y + sin z then possible value of x - y 2 is R. If ( 4 - x ) 2x + x 2x x = x 2x x + ( 4 + x ) 2x then possible value of sec x is S. If ( ^ -1 1 - x^2 ) = ( ^ -1 (x 6 ) ), x ≠ 0, then possible value of x is List II 1. 1 2 5 3 2. 2 3. 1 2 4. 1

Accepted Answer

(B)

JEE Advanced 2013 Mathematics question

Solution

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