JEE Advanced 2015 Mathematics question

MathematicsApplication of DerivativesJEE Advanced 2015

Let be a continuous odd function, which vanishes exactly at one point and . Suppose that for all and for all . If , then the value of is

Answer: 7

Solution

is odd, so . In , is odd and is even (), so the integrand is odd and . The limit is ; by L'Hospital's rule

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Question ID VK-026470