JEE Advanced 2016 Chemistry question
One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm. In this process, the change in entropy of surroundings () in J K is (1 L atm = 101.3 J)
Answer: (C)
Solution
Work done on the gas: L atm J. For an isothermal process of an ideal gas , so J, which is absorbed from the surroundings. $Δ
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