JEE Advanced 2016 Physics question
A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pa and volume m changes to a final state at Pa and m in an adiabatic quasi-static process, such that = constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at followed by an isochoric (isovolumetric) process at volume . The amount of heat supplied to the system in the two-step process is approximately
Solution
= constant is the adiabatic law = constant, so . Change in internal energy (state function, same for any path): J. Work in the
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