JEE Advanced 2016 Physics question
The ends Q and R of two thin wires, PQ and RS, are soldered (joined) together. Initially each of the wires has a length of 1 m at 10 °C. Now the end P is maintained at 10 °C, while the end S is heated and maintained at 400 °C. The system is thermally insulated from its surroundings. If the thermal conductivity of wire PQ is twice that of the wire RS and the coefficient of linear thermal expansion of PQ is , the change in length of the wire PQ is
Solution
In the steady state the same heat current flows through both wires (equal lengths and cross-sections): C at the junction. The temperature along PQ rises linearly from 10 °C to 140 °C, so the average rise above
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