Let f(x) : cases x, & x is rational 0, & x is irrational cases and g(x) : cases 0, & x is rational , & x is irrational cases If f : R R and g : R R , then (f-g) is

NDA 2017 Mathematics question

Let and If and , then is

Answer: (D)

for rational and for irrational . Rationals are mapped to rationals (each to itself) and irrationals to irrationals (each to its negative), so

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Question ID VK-028652