The observations 4, 1, 4, 3, 6, 2, 1, 3, 4, 5, 1, 6 are outputs of 12 dices thrown simultaneously. If m and M are means of lowest 8 observations and highest 4 observations respectively, then what is (2m+M) equal to?

NDA 2023 Mathematics question

The observations 4, 1, 4, 3, 6, 2, 1, 3, 4, 5, 1, 6 are outputs of 12 dices thrown simultaneously. If and are means of lowest 8 observations and highest 4 observations respectively, then what is equal to?

(A)10Correct
(B)12
(C)17
(D)21

Answer: (A)

Solution

In ascending order: 1, 1, 1, 2, 3, 3, 4, 4, 4, 5, 6, 6. Lowest 8: sum , so $m =

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Question ID VK-029639