The force acting on a particle of mass m moving along the x-axis is given by F(x) = Ax^2 - Bx. Which one of the following is the potential energy of the particle ?

NDA 2017 Physics question

The force acting on a particle of mass m moving along the x-axis is given by . Which one of the following is the potential energy of the particle ?

Answer: (B)

For a conservative force, , so U = -\displaystyle\int F\,dx = -\int (Ax^2 - Bx)\,dx = -\dfrac{Ax^3}{3} + \dfrac{Bx^2}{2}

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Question ID VK-030861