Starting at time t = 0 from the origin with speed 1 ms ^ -1 , a particle follows a two-dimensional trajectory in the x-y plane so that its coordinates are related by the equation y = x^2 2 . The x and y components of its acceleration are denoted by a_x and a_y, respectively. Then

JEE Advanced 2020 Physics question

Physics Motion in a Plane JEE Advanced 2020

Starting at time from the origin with speed , a particle follows a two-dimensional trajectory in the - plane so that its coordinates are related by the equation . The and components of its acceleration are denoted by and , respectively. Then

(A) implies that when the particle is at the origin, Correct
(B) implies at all timesCorrect
(C)at , the particle's velocity points in the -directionCorrect
(D) implies that at s, the angle between the particle's velocity and the axis is Correct

Answer: (A),(B),(C),(D)

Solution

Differentiating : and . (C) At , so ; the velocity (speed 1 m/s) is along with m/s – correct. (A) At the origin whatever the value of , in particular for $ = 1\

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Question ID VK-033797