JEE Advanced 2021 Chemistry question
Some standard electrode potentials at 298 K are given below: V V V V To a solution containing 0.001 M of and 0.1 M of , the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y, respectively, is(are) (Given: Gas constant, R = 8.314 J K mol, Faraday constant, F = 96500 C mol)
Answer: (A),(B),(C)
Solution
X dissolves, so X is the anode: . Nernst equation: \circ_{Y}\circ_{X}\dfrac{0.0591}{2}$ = E^-E^-0.02955 =
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