JEE Advanced 2022 Chemistry question
2 mol of Hg(g) is combusted in a fixed volume bomb calorimeter with excess of at 298 K and 1 atm into HgO(s). During the reaction, temperature increases from 298.0 K to 312.8 K. If heat capacity of the bomb calorimeter and enthalpy of formation of Hg(g) are 20.00 kJ K and 61.32 kJ mol at 298 K, respectively, the calculated standard molar enthalpy of formation of HgO(s) at 298 K is X kJ mol. The value of |X| is . [Given: Gas constant R = 8.3 J K mol]
Answer: 90.39
Solution
Reaction: . At constant volume the heat released is kJ, so kJ. : n_gRT$ =
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