JEE Advanced 2022 Mathematics question
Consider 4 boxes, where each box contains 3 red balls and 2 blue balls. Assume that all 20 balls are distinct. In how many different ways can 10 balls be chosen from these 4 boxes so that from each box at least one red ball and one blue ball are chosen ?
Answer: (A)
Solution
From one box, choosing at least one red and one blue: 2 balls in ways; 3 balls in ways; 4 balls in ways; 5 balls in 1 way. Generating function per box:
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