For positive integer n, define f(n) = n + 16 + 5n - 3n^2 4n + 3n^2 + 32 + n - 3n^2 8n + 3n^2 + 48 - 3n - 3n^2 12n + 3n^2 + + 25n - 7n^2 7n^2 . Then, the value of _ n f(n) is equal to

JEE Advanced 2022 Mathematics question

For positive integer , define

f(n) = n + + + + ·s + .

Then, the value of is equal to

Answer: (B)

The -th fraction is for (for : ). Then , so \sum_{k=1}^nT_k$ =

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Question ID VK-034025