JEE Advanced 2023 Physics question
A series LCR circuit is connected to a Volt source. The resonant angular frequency of the circuit is rad s and current amplitude at resonance is . When the angular frequency of the source is rad s, the current amplitude in the circuit is . If mH, match each entry in List-I with an appropriate value from List-II and choose the correct option. List-I (P) in mA (Q) The quality factor of the circuit (R) The bandwidth of the circuit in rad s (S) The peak power dissipated at resonance in Watt List-II (1) 44.4 (2) 18 (3) 400 (4) 2250 (5) 500
Answer: (B)
Solution
F. At : . Current is , so : $ = + ⇒ R =
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