JEE Advanced 2023 Chemistry question
50 mL of 0.2 molal urea solution (density = 1.012 g mL at 300 K) is mixed with 250 mL of a solution containing 0.06 g of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in Torr) of the resulting solution at 300 K is . [Use: Molar mass of urea = 60 g mol; gas constant, R = 62 L Torr K mol; Assume, , ]
Answer: 682
Solution
First solution: mass g. If it contains g solvent, urea mol, i.e. g; $w+0.012w = 50.6 ⇒ w =
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