Define , . Let denote the number of solutions of the equation in the interval and . Then the value of is equal to .
Answer: 5
Solution
, , , , , and is linear between consecutive odd integers; so its graph is a zig-zag with zeros at . Areas: on a triangle of area ; on a triangle of area ; on area ; on area . Hence increases from
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.