JEE Main 2022 Physics question
A body of mass 10 kg is projected at an angle of 45° with the horizontal. The trajectory of the body is observed to pass through a point (20, 10). If T is the time of flight, then its momentum vector, at time , is . [Take g = 10 ]
Answer: (4)
Solution
The trajectory is y = x − x/R). Through (20, 10): 10 = 20(1 − 20/R), so R = 40. From , u = 20 m/s. The time of flight is T = 2u s, so $t =
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