JEE Main 2022 Physics question
A cyclotron is used to accelerate protons. If the operating magnetic field is 1.0 T and the radius of the cyclotron 'dees' is 60 cm, the kinetic energy of the accelerated protons in MeV will be [Use = kg, C]
Answer: (2)
Solution
R = mv/(Bq) = , so B^{2}q^{2}R^{2}$/(2m) = (1.6 ×
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