JEE Main 2022 Chemistry question

Match List-I with List-II List-I (Mixture): (A) Chloroform & Aniline (B) Benzoic acid & Napthalene (C) Water & Aniline (D) Napthalene & Sodium chloride List-II (Purification Process): (I) Steam distillation (II) Sublimation (III) Distillation (IV) Crystallisation Choose the correct answer from the options given below:

(1)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(2)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
(3)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
(4)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)Correct

Answer: (4)

Solution

Chloroform and aniline differ widely in boiling point, so they are separated by simple distillation (III). Benzoic acid and naphthalene (both sublime) are separated by crystallisation (IV).

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Question ID VK-034314