JEE Main 2022 Chemistry question
For a real gas at 25°C temperature and high pressure (99 bar) the value of compressibility factor is 2, so the value of Van der Waal's constant 'b' should be L (Nearest integer) (Given R = 0.083 L bar )
Answer: 25
Solution
At high pressure P(V − b) = RT, so Z = PV/RT = 1 + Pb/RT. With Z = 2: 1 = Pb/RT, so
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