JEE Main 2022 Mathematics question
Let X have a binomial distribution B(n, p) such that the sum and the product of the mean and variance of X are 24 and 128 respectively. If , then k is equal to
Answer: (2)
Solution
Let the mean be np and the variance npq. np + npq = 24 and (np)(npq) = 128, so np = 16 and npq = 8 (the other solution gives p > 1). So q = 1/2, p = 1/2 and n =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account