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JEE Main 2022 Mathematics question

MathematicsTrigonometric Ratio and IdentitiesJEE Main 2022

Let Extra open brace or missing close braceS = {\theta \in (0, ) : Extra close brace or missing open brace\Sigma \_{m=1}^{9} \sec (\theta + (m - 1)\pi /6) \sec (\theta + m\pi /6) = -8/\sqrt{3}}. Then

Answer: (3)

Solution

Using sec A sec B = (1/sin(B − A))(tan B − tan A) with , each term equals . The sum telescopes to − tan ] = 2(−cot

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Question ID VK-034344