JEE Main 2022 Physics question
Sand is being dropped from a stationary dropper at a rate of 0.5 on a conveyour belt moving with a velocity of 5 . The power needed to keep the belt moving with the same velocity will be
Answer: (4)
Solution
The force needed to keep the belt moving is F = v(dm/dt) = N. The power is P = F·v = W.