At 310 K, the solubility of CaF_ 2 in water is 2.34 10^ -3 g/100 mL. The solubility product of CaF_ 2 is _____ 10^ -8 (mol/L)^ 3 . (Given molar mass: CaF_ 2 = 78 g mol^ -1 )

JEE Main 2022 Chemistry question

At 310 K, the solubility of in water is g/100 mL. The solubility product of is . (Given molar mass: g )

Answer: 0

The solubility is 10)/78 = mol/L. For , =

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Question ID VK-034411