JEE Main 2022 Mathematics question
Let y = y(x) be the solution curve of the differential equation x , , which passes through the point (, 1). Then is equal to .
Answer: 1
Solution
Divide by ln(tan ) dx: dy/dx + ln(tan x ln(tan )). The integrating factor is dx/(sin ln tan ). With , y ln(tan \int\sqrt{2}$
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