JEE Main 2022 Physics question
One end of a massless spring of spring constant k and natural length is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity about an axis passing through fixed end, then the elongation of the spring will be :
Answer: (3)
Solution
The spring force provides the centripetal force: kx = . So
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account