JEE Main 2022 Physics question
A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is . The value of x is (Given, g = 10 )
Answer: 3
Solution
For the upper half of the rope, T = mg = 100 N and T
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account