JEE Main 2022 Physics question
A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is s.
Answer: 1
Solution
Taking x = A from the position of maximum displacement, x = A/2 when , i.e. t = T/6 = 1 s.