JEE Main 2022 Chemistry question
It has been found that for a chemical reaction with rise in temperature by 9 K the rate constant gets doubled. Assuming a reaction to be occurring at 300 K, the value of activation energy is found to be kJ . [nearest integer] (Given ln10 = 2.3, R = 8.3 J , log 2 = 0.30)
Answer: 59
Solution
K, K and . From $ / = /2. -
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