JEE Main 2022 Physics question
In young's double slit experiment the two slits are 0.6 mm distance apart. Interference pattern is observed on a screen at a distance 80 cm from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be nm.
Answer: 450
Solution
The first dark fringe is directly opposite one slit, so y = d/2. The path difference is = yd/D = , and for
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