JEE Main 2022 Physics question
A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is nJ.
Answer: 125
Solution
The initial energy is . After sharing the charge equally with an identical capacitor the final energy is half of this, so the energy
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account